0=14x^2-54x+36

Solution for 0=14x^2-54x+36 equation:

0=14x^2-54x+36

We move all terms to the left:

0-(14x^2-54x+36)=0

We add all the numbers together, and all the variables

-(14x^2-54x+36)=0

We get rid of parentheses

-14x^2+54x-36=0

a = -14; b = 54; c = -36;
Δ = b2-4ac
Δ = 542-4·(-14)·(-36)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-30}{2*-14}=\frac{-84}{-28}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+30}{2*-14}=\frac{-24}{-28}
=6/7
$